python实现打扑克方法

发布时间 2023-12-29 11:04:37作者: 杨梅冲

# 游戏规则:
# 一付扑克牌,去掉大小王,每个玩家发3张牌,最后比大小,看谁赢。
#
# 有以下几种牌:
# 豹子:三张一样的牌,如3张6.
# 同花顺:即3张同样花色的顺子, 如红桃 5、6、7
# 顺子:又称拖拉机,花色不同,但是顺子,如红桃5、方片6、黑桃7,组成的顺子
# 对子:2张牌一样
# 单张:单张最大的是A
# 这几种牌的大小顺序为, 豹子>同花顺>同花>顺子>对子>单张


# 需程序实现的点:
# 1. 先生成一付完整的扑克牌
# 2. 给5个玩家随机发牌
# 3. 统一开牌,比大小,输出赢家是谁
# 3.1 单牌之间如何比较大小 (权重)
# 3.2 其他牌型如何比较大小
# A:红桃J 红桃K 黑桃A 1.1 13 140 = 154.1
#
# B:方片2 方片2 梅花3 0.2 2 30 = 32.2*5 = 161

# 3.3 判断玩家手里是什么牌(不同的牌型有不同的判断方法)高内聚 低耦合
# val = [2, 2, 3] # SET
# if len(set(val)) == 2: # {2, 3}
# print("对子")
#
# if len(set(val)) == 1:
# print("豹子")

# 代码实现
import random


# 1. 生成牌
def alex():
poke_types = ['♥', '♠', '♦', '♣']
poke_nums = [2, 3, 4, 5, 6, 7, 8, 9, 10, 'J', 'Q', 'K', 'A']
poke_list = []
for p_type in poke_types:
count = 2
for p_num in poke_nums:
card = [f"{p_type}{p_num}", count]
poke_list.append(card)
count += 1
# print(poke_list)
return poke_list


pokeList = alex()

# 2. 发牌
players = ['木木', '鬼鬼', '神经蛤蟆', 'error', '裕', '感叹号']


def blackGirl(pl, pk, pn):
player_dic = {}
for p_name in pl:
p_cards = random.sample(pk, pn)
for card in p_cards:
pk.remove(card)
player_dic[p_name] = p_cards
print(f"为玩家【{p_name}】生成了牌:{p_cards}")
return player_dic


playerDic = blackGirl(players, pokeList, 3)


# 3. 写好每种牌型的判断函数
# 冒泡排序
def sortList(dataList):
length = len(dataList)
for i in range(length):
for j in range(length - i - 1):
if dataList[j][1] > dataList[j + 1][1]:
dataList[j], dataList[j + 1] = dataList[j + 1], dataList[j]
return dataList


# 单张
def calculate_single(p_cards, score):
# 初始化
# score = 0

# 算分 0.1 1 10
# 先排序
p_cards = sortList(p_cards)
weight_val = [0.1, 1, 10]
count = 0
for card in p_cards:
score += card[1] * weight_val[count]
count += 1

print(f"计算单牌的结果是:{score}")
return score


# 对子
def calculate_pair(p_cards, score):
p_cards = sortList(p_cards)
# 列表推导式
card_val = [i[1] for i in p_cards]

if len(set(card_val)) == 2:
if card_val[0] == card_val[1]: # aab
score = (card_val[0] + card_val[1]) * 50 + card_val[2]
else: # abb
score = (card_val[1] + card_val[2]) * 50 + card_val[0]

print(f"计算对子的结果是:{score}")
return score


# 顺子
def calculate_straight(p_cards, score):
p_cards = sortList(p_cards)

card_val = [i[1] for i in p_cards]
a, b, c = card_val
if b - a == 1 and c - b == 1:
score *= 100
print(f"计算顺子的结果是:{score}")
return score


# 同花
def calculate_same_color(p_cards, score):
color_val = [i[0][0] for i in p_cards]
if len(set(color_val)) == 1:
score *= 1000
print(f"计算同花的结果是:{score}")
return score


# 同花顺
def calculate_same_color_straight(p_cards, score):
# 同花
color_val = [i[0][0] for i in p_cards]
if len(set(color_val)) == 1:
# 顺子
p_cards = sortList(p_cards)

card_val = [i[1] for i in p_cards]
a, b, c = card_val
if b - a == 1 and c - b == 1:
score *= 0.1
print(f"计算同花顺的结果是:{score}")
return score


# 豹子
def calculate_leopard(p_cards, score):
card_val = {i[1] for i in p_cards}

if len(card_val) == 1:
score *= 100000
print(f"计算豹子的结果是:{score}")
return score


# 4. 比对
calc_func_orders = [
calculate_single,
calculate_pair,
calculate_straight,
calculate_same_color,
calculate_same_color_straight,
calculate_leopard
]
player_score = []
for p_name, p_cards in playerDic.items():
print(f"开始计算玩家【{p_name}】的牌:{p_cards}")
score = 0
for calc_func in calc_func_orders:
score = calc_func(p_cards, score)
player_score.append([p_name, score])


winner = sortList(player_score)[-1]

print(f"恭喜最后获胜的玩家是【{winner[0]}】,得分是:{winner[1]}")