A. Nastia and Nearly Good Numbers
https://codeforces.com/problemset/problem/1521/A
"""
思路：
1.就是普通的打印，NO的情况是只有b=1的时候才会出现，其他的都是YES，如果不想再继续分情况就把a*b放在中间做y，或者做x也可，避免(b-1) = 1, 最后要x + y = z
"""
for line in [*open(0)][1:]:
a, b = [int(i) for i in line.split()]
if b == 1:
print("NO")
else:
print("YES")
print(f"{a} {a * b} {a * (b+1)}")