python计算两个矩形的重叠_python计算两个矩形框重合百分比的实例

发布时间 2023-11-29 17:08:21作者: 苹果芒

如下所示:

def mat_inter(box1,box2):
   # 判断两个矩形是否相交
   # box=(xA,yA,xB,yB)
  x01, y01, x02, y02 = box1
  x11, y11, x12, y12 = box2
  lx = abs((x01 + x02) / 2 - (x11 + x12) / 2)
  ly = abs((y01 + y02) / 2 - (y11 + y12) / 2)
  sax = abs(x01 - x02)
  sbx = abs(x11 - x12)
  say = abs(y01 - y02)
  sby = abs(y11 - y12)
  if lx <= (sax + sbx) / 2 and ly <= (say + sby) / 2:
    return True
  else:
    return False

def solve_coincide(box1,box2):
  # box=(xA,yA,xB,yB)
  # 计算两个矩形框的重合度
  if mat_inter(box1,box2)==True: #判断两个矩形是否有交叉
    x01, y01, x02, y02 = box1
    x11, y11, x12, y12 = box2
    col=min(x02,x12)-max(x01,x11)
    row=min(y02,y12)-max(y01,y11)
    intersection=col*row
    area1=(x02-x01)*(y02-y01)
    area2=(x12-x11)*(y12-y11)
    coincide=intersection/(area1+area2-intersection)
    return coincide
  else:
    return 0