Leaf-Similar Trees
Thinkings
二叉树无论先中后序遍历,所得叶子节点次序不变.
Codes
我采用了非递归的中序遍历方式:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left),
* right(right) {}
* };
*/
class Solution {
public:
bool leafSimilar(TreeNode* root1, TreeNode* root2) {
std::vector<int> leaf1;
std::vector<int> leaf2;
// InOrder Traverse
std::stack<TreeNode*> stack1;
TreeNode* p1 = root1;
while (p1 || !stack1.empty()) {
if (p1) {
stack1.push(p1);
p1 = p1->left;
} else {
p1 = stack1.top();
stack1.pop();
if (!p1->right) {
leaf1.push_back(p1->val);
}
p1 = p1->right;
}
}
std::stack<TreeNode*> stack2;
TreeNode* p2 = root2;
while (p2 || !stack2.empty()) {
if (p2) {
stack2.push(p2);
p2 = p2->left;
} else {
p2 = stack2.top();
stack2.pop();
if (!p2->right) {
leaf2.push_back(p2->val);
}
p2 = p2->right;
}
}
return leaf1 == leaf2;
}
};
Notes
vector
std::vector - cppreference.com