133e
[arc133e]Cyclic Medians
E - Cyclic Medians 看到中位数,就是经典套路:将\(\geq\)中位数的都赋值为\(1\),\(<\)的赋值为\(0\) 那么对于数\(A\),就等于\(\sum_{i=1}^{\infty}[A\geq i]\) 所以我们考虑枚举中位数,然后若其\(\leq A\),那么就对答案 ......
ARC133E 题解
# [ARC133E] Cyclic Medians 题解 ## Links [Luogu](https://www.luogu.com.cn/problem/AT_arc133_e) [AtCoder](https://atcoder.jp/contests/arc133/tasks/arc133 ......