算法战斗第三天C++1-526互联

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

Operation ++ increases the value of variable x by 1.
Operation -- decreases the value of variable x by 1.

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input：The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output：Print a single integer — the final value of x.

Examples

Input

1
++X

Output

Input

2
X++
--X

Output

题解思路：就是识别几个语句读入，然后找＋还是-；string 定义s 然后s[1]取值会报错，得用char定义；

#include<iostream>
using namespace std;

int main(){
	int n=0,i,x=0;
	char s[4];
	cin>>n;
	while(n--&&(1<=n<=150)){
		cin>>s;
		
		if(s[1]=='+'){
			x++;
		}else{
			x--;
		}			
	}
	cout<<x<<endl;
}